Sử dụng BĐT \(\left(x+y+z\right)^2\ge3\left(xy+yz+zx\right)\)
Ta có:
\(P^2=\left(\frac{ab}{c}+\frac{bc}{a}+\frac{ac}{b}\right)^2\ge3\left(\frac{ab.bc}{ac}+\frac{ab.ac}{bc}+\frac{bc.ac}{ab}\right)=3\)
\(\Rightarrow P\ge\sqrt{3}\)
\(P_{min}=\sqrt{3}\) khi \(a=b=c=\frac{1}{\sqrt{3}}\)