\(log_{c+b}a+log_{c-b}a=\frac{1}{log_a\left(c+b\right)}+\frac{1}{log_a\left(c-b\right)}\)
\(=\frac{log_a\left(c-b\right)+log_a\left(c+b\right)}{log_a\left(c-b\right).log_a\left(c+b\right)}=\frac{log_a\left(c^2-b^2\right)}{log_a\left(c-b\right)log_a\left(c+b\right)}\)
\(=log_aa^2.log_{\left(c+b\right)}a.log_{c-b}a=2log_{c+b}a.log_{c-b}a\)