\(a+b=ab=\dfrac{a}{b}\)
Ta có:
\(ab=\dfrac{a}{b}\Rightarrow ab=\dfrac{a^2}{ab}\)
\(\Rightarrow a^2b^2=a^2\)
\(\Rightarrow b^2=1\Rightarrow b=\pm1\)
Xét:
\(b=1\Rightarrow a+b=ab=\dfrac{a}{b}\Rightarrow a+1=a=a\left(KTM\right)\)
Xét:
\(b=-1\Rightarrow a+b=ab=\dfrac{a}{b}\Rightarrow a-1=-a=-a\)
\(\Rightarrow a-1=-a\)
\(\Rightarrow2a=1\Rightarrow a=\dfrac{1}{2}\)
Ta có:
\(\dfrac{a}{b}=a-1\rightarrowđpcm\)
\(b=-1\rightarrowđpcm\)
\(a=\dfrac{1}{2}\)