Question

Cho 2 đa thức:

P(x) = \(2x^{2} - 5x - \frac{1}{3}\)

và Q(x) = \(-6x^{4} + 5x^{2} + \frac{2}{3} + 3x\)

Tình hiệu P(x) - Q(x)

Answer 1

Có: \(P\left(x\right)-Q\left(x\right)=\left(2x^2-5x-\dfrac{1}{3}\right)-\left(-6x^4+5x^2+\dfrac{2}{3}+3x\right)\)

\(P\left(x\right)-Q\left(x\right)=2x^2-5x-\dfrac{1}{3}+6x^4-5x^2-\dfrac{2}{3}-3x\)

\(P\left(x\right)-Q\left(x\right)=6x^4+\left(2x^2-5x^2\right)-\left(5x+3x\right)-\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)

\(P\left(x\right)-Q\left(x\right)=6x^4-3x^2-8x-1\)