\(n_{CuO}=\dfrac{10}{80}=0,125\left(mol\right)\)
\(CuO+2HCl\rightarrow CuCl_2+H_2O\)
\(\Rightarrow n_{HCl}=2n_{CuO}=0,25\left(mol\right)\)
\(\Rightarrow V_{dd}=\dfrac{0,25}{3}=\dfrac{1}{12}\left(l\right)\)
\(n_{CuCl_2}=n_{CuO}=0,125\left(mol\right)\)
\(\Rightarrow C_{M\left(CuCl_2\right)}=\dfrac{0,125}{\dfrac{1}{12}}=1,5M\)