Bt1 ;Bỏ dấu ngặc rồi thực hiện phép tính
a, -3\(+\)\((\)-4\()\)-\((\)-3\()\)\(+\)\((\)2\(+\)7-10\()\)
b, 3- \((\)-3\(+\)2-7\()\)\(+\)\((\)-4\()\)
c, 7\(+\)\((\)-2-3\(+\)7\()\)-\((\)-2\()\)
d, -\((\)-3\()\)-\((\)-2\(+\)3-8\()\)\(+\)\((\)-6\()\)
Bt2; Rút gọn ;
a, x2-2x-\((\)3x -2x \()\)
b, -\((\)x2\(+\)3x2\()\)-\((\)-5x2\(+\)3x\()\)
c, \((\)x-y \()\)- \((\)x\(+\)3y \(+\)1\()\)
Bài 1 :
a) \(-3+\left(-4\right)-\left(-3\right)+\left(2+7-10\right)=-3-4+3+2+7-10=-5\)
b) \(3-\left(-3+2-7\right)+\left(-4\right)=3+3-2+7-4=7\)
c) \(7+\left(-2-3+7\right)-\left(-2\right)=7-2-3+7+2=17\)
d) \(-\left(-3\right)-\left(-2+3-8\right)+\left(-6\right)=3+2-3+8-6=4\)
Bài 2 :
a) \(x^2-2x-\left(3x-2x\right)=x^2-2x-3x+2x=x^2-3x\)
b) \(-\left(x^2+3x^2\right)-\left(-5x^2+3x\right)=-x^2-3x^2+5x^2-3x=x^2-3x\)
c) \(\left(x-y\right)-\left(x+3y+1\right)=x-y-x-3y-1=-4y-1\)
Bài 1:
a, -3+ (-4) - (-3) + (2 + 7 - 10)
= -3 - 4 + 3 + 2 + 7 - 10
= 5 - 10
= -5.
b, 3 - (-3 + 2 - 7) + (-4)
= 3 + 3 - 2 + 7 - 4
= 11 - 4
= 7
c, 7 + (-2 - 3 + 7) - (-2)
= 7 - 2 - 3 + 7 + 2
= 9 + 2
= 11.
d, - (-3) - (-2 + 3 - 8) + (-6)
= 3 + 2 - 3 + 8 - 6
= 10 - 6
= 4.
Mình chỉ làm bài 1 thôi nhé.
Chúc bạn học tốt!
