Question

bai: Thuc hien phep tinh bang cach hop ly nhat:

a) \((\frac{1}{5}-\frac{1}{4})^2\)

b) \((\frac{5}{3}+\frac{1}{2}):\frac{-13}{5}+1\frac{5}{6}\)

c) \((\frac{3}{17})^4.(\frac{-17}{6})^4\)

Answer 1

a, \(\left(\frac{1}{5}-\frac{1}{4}\right)^2=\left(\frac{-1}{20}\right)^2=\frac{1}{400}\)

b, \(\left(\frac{5}{3}+\frac{1}{2}\right):\frac{-13}{5}+1\frac{5}{6}\)

=> \(\frac{13}{6}:\frac{-13}{5}+\frac{11}{6}\)

=> \(\frac{13}{6}.\frac{5}{-13}+\frac{11}{6}\)

=> \(\frac{-5}{6}+\frac{11}{6}=\frac{6}{6}=1\)

c, \(\left(\frac{3}{17}\right)^4.\left(\frac{-17}{6}\right)^4\)

=> \(\left(\frac{3}{17}.\frac{-17}{6}\right)^4=\left(\frac{-1}{2}\right)^4=\frac{1}{16}\)

Answer 2

đúng 100%

Answer 3

a) \(\left(\frac{1}{5}-\frac{1}{4}\right)^2=\left(-\frac{1}{20}\right)^2=\frac{1}{400}.\)

b) \(\left(\frac{5}{3}+\frac{1}{2}\right):-\frac{13}{5}+1\frac{5}{6}\)

= \(\frac{13}{6}:\left(-\frac{13}{5}\right)+\frac{11}{6}\)

= \(\left(-\frac{5}{6}\right)+\frac{11}{6}\)

= \(1.\)

c) \(\left(\frac{3}{17}\right)^4.\left(-\frac{17}{6}\right)^4\)

= \(\left[\frac{3}{17}.\left(-\frac{17}{6}\right)\right]^4\)

= \(\left(-\frac{1}{2}\right)^4=\frac{1}{16}.\)

Chúc bạn học tốt!