Question

bai: \((2-\frac{13}{8}+\frac{1}{4})(\frac{-2}{3})^2\)

Answer 1

\(\left(2-\frac{13}{8}+\frac{1}{4}\right)\left(\frac{-2}{3}\right)^2\\ =\left(\frac{3}{8}+\frac{2}{8}\right)\cdot\frac{4}{9}\\ =\frac{5}{8}\cdot\frac{4}{9}\\ =\frac{5}{18}\)

Answer 2

\(\left(2-\frac{13}{8}+\frac{1}{4}\right)\left(-\frac{2}{3}\right)^2\)

= \(\left(\frac{3}{8}+\frac{1}{4}\right).\frac{4}{9}\)

= \(\frac{5}{8}.\frac{4}{9}\)

= \(\frac{5}{18}.\)

Chúc bạn học tốt!

Answer 3

\(\left(2-\frac{13}{8}+\frac{1}{4}\right).\left(-\frac{2}{3}\right)^2\)

\(=\left(\frac{3}{8}+\frac{2}{8}\right).\frac{4}{9}\)

\(=\frac{5}{8}.\frac{4}{9}\)

\(=\frac{5}{18}\)

Vậy : \(\left(2-\frac{13}{8}+\frac{1}{4}\right).\left(-\frac{2}{3}\right)^2=\frac{5}{18}\)