a) 0,(5)+0,(3)+0,(1)
=\(\frac{5}{9}\)+\(\frac{1}{3}\)+\(\frac{1}{9}\)
=\(\frac{5}{9}\)+\(\frac{3}{9}\)+\(\frac{1}{9}\)
=\(\frac{5+3+1}{9}\)
=\(\frac{9}{9}\)
=1
b) 0,(57)+0,(42)
=\(\frac{19}{33}\)+\(\frac{14}{33}\)
=\(\frac{19+14}{33}\)
=\(\frac{33}{33}\)
=1
Chúc cậu học tốt •ω•
a/ 0,(5) + 0,(3) + 0,(1) = 1
b/ 0,(57) + 0,(42) = 1