a. ( 2x - 5) ( x -3 ) = \(2x^2\)
=> \(2x^2-6x-5x+15\) = \(^{ }2x^2\)
=> \(2x^2-2x^2-6x-5x=-15\)
=> -11x = -15
=> x = \(\dfrac{15}{11}\)
b. (-2x+1)(4x-1)=(7-x).8x
=> \(^{ }-8x^2+2x+4x-1=56x-8x^2\)
=> \(^{ }-8x^2+8x^2+2x+4x-56x=1\)
=> -50x = 1
=> x = \(\dfrac{-1}{50}\)
c. \(x^2-16=0\)
=> \(x^2=16\)
=> TH1: x = 4
TH2: x = -4
d, (3x-2)(3x-1)=\(_{^{ }}\left(3x-1\right)^2\)
=> \(\left(3x-2\right)\left(3x-1\right)-\left(3x-1\right)^2\) = 0
=> ( 3x - 1 ) ( 3x-2 + 3x - 1 ) = 0
=> 3x-1 = 0 và 6x -2 - 1 = 0
=> x = \(\dfrac{1}{3}\) và x = \(\dfrac{1}{2}\)
