a: Ta có: \(\sqrt{252}-\sqrt{700}+\sqrt{1008}-\sqrt{448}\)
\(=6\sqrt{7}-10\sqrt{7}+12\sqrt{7}-8\sqrt{7}\)
\(=0\)
b: Ta có: \(\left(\sqrt{125}+\sqrt{245}-\sqrt{5}\right):\sqrt{5}\)
\(=5+7-1\)
=11
BT: Tính
a, \(\sqrt{13}.\sqrt{52}\)
b, \(\sqrt{12,5}.\sqrt{0,2}.\sqrt{0,1}\)
c, \(\sqrt{12}-\sqrt{27}+\sqrt{3}\)
d, \(\sqrt{252}-\sqrt{700}+\sqrt{1008}-\sqrt{448}\)
e, \(\left(\sqrt{12}-2\sqrt{75}\right).\sqrt{3}\)
f, \(\sqrt{3}.\left(\sqrt{12}+\sqrt{27}-\sqrt{3}\right)\)
g, \(\left(\sqrt{18}+\sqrt{32}-\sqrt{50}\right).\sqrt{2}\)
h, \(\sqrt{50}-\sqrt{18}+\sqrt{200}-\sqrt{162}\)
k, \(\frac{\sqrt{6}+\sqrt{10}}{\sqrt{21}+\sqrt{35}}\)
l, \(\frac{\sqrt{405}+3\sqrt{27}}{3\sqrt{3}+\sqrt{45}}\)
m, \(\frac{\sqrt{2}+\sqrt{3}+\sqrt{4}-\sqrt{6}-\sqrt{9}-\sqrt{12}}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\)
n, \(\frac{\sqrt{6-2\sqrt{5}}}{\sqrt{5}-1}\)
p, \(\left(3+\sqrt{5}\right)\left(3-\sqrt{5}\right)-\left(2+\sqrt{3}\right)\left(2-\sqrt{3}\right)\)
q, \(2\sqrt{3}\left(\sqrt{2}-3\right)+\left(2-\sqrt{3}\right)^2+6\sqrt{3}\)
1.Thực hiện phép tính:
a.\(\sqrt{12}-\sqrt{27}+\sqrt{3}\)
b.\(\left(\sqrt{12}-2\sqrt{75}\right)\sqrt{3}\)
c.\(\sqrt{225}-\sqrt{700}+\sqrt{1008}-\sqrt{448}\)
d.\(\sqrt{3}\left(\sqrt{12}+\sqrt{27}-\sqrt{3}\right)\)
bài 1 ; thực hiện phép tính
a, \(\left(\sqrt{12}+\sqrt{75}+\sqrt{27}\right):\sqrt{15}\)
b, \(\sqrt{252}-\sqrt{700}+\sqrt{1008}-\sqrt{448}\)
c, \(\sqrt{27^2-23^2}+\sqrt{37^2-35^2}\)
d,\(\left(\sqrt{\dfrac{1}{7}}+\sqrt{\dfrac{16}{7}}+\sqrt{\dfrac{9}{7}}\right):\sqrt{7}\)
bài 2 : rút gọn
a, \(A=\dfrac{2}{x^2-y^2}\times\sqrt{\dfrac{3x^2+6xy+3y^2}{4}}\)
b, \(B=\dfrac{1}{2a-1}\times\sqrt{5a^4\left(1-4a+4a^2\right)}\)
tính
\(a.\sqrt{0,45.0,36}\)
b.\(\dfrac{\sqrt{405}+3\sqrt{27}}{3\sqrt[]{3}+45}\)
c.\(\sqrt{252}-\sqrt{700}+\sqrt{1008}-\sqrt{448}\)
d.\(\left(\sqrt{12}-2\sqrt{75}\right)\sqrt{3}\)
Thực hiện phép tính:
a) ( \(4+\sqrt{15}\))\(\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
b)\(\sqrt{3-\sqrt{5}}\left(3+\sqrt{5}\right)\left(\sqrt{10}-\sqrt{2}\right)\)
c) \(\left(\sqrt{3}-\sqrt{2}+1\right)\left(\sqrt{3}-1\right)\)
d) \(\sqrt{2+\sqrt{3}}.\sqrt{2+\sqrt{2+\sqrt{3}}}.\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{3}}}}.\sqrt{2-\sqrt{2+\sqrt{2+\sqrt{3}}}}\)
Tính
1) \(\sqrt{18}.\sqrt{2}\)
2) \(\sqrt{15^2-9^2}\)
3) \(\sqrt{46-6\sqrt{5}}-\sqrt{46+6\sqrt{5}}\)
4)\(\sqrt{21+6\sqrt{6}}-\sqrt{21-6\sqrt{6}}\)
5) \(\left(2+\sqrt{5}\right).\sqrt{9-4\sqrt{5}}\)
6)\(\left(3-\sqrt{2}\right).\sqrt{7+4\sqrt{3}}\)
7)\(\left(\sqrt{3}+\sqrt{5}\right).\sqrt{7-2\sqrt{10}}\)
8)\(\left(\sqrt{6}+\sqrt{10}\right).\sqrt{4-\sqrt{15}}\)
9) \(\sqrt{2}.\left(\sqrt{8}-\sqrt{32}+3\sqrt{18}\right)\)
10) \(\sqrt{2}\left(\sqrt{2}-\sqrt{3-\sqrt{5}}\right)\)
11) \(\sqrt{3}-\sqrt{2}-\sqrt{\left(\sqrt{3}+\sqrt{2}\right)^2}\)
12) \(\left(\sqrt{2}-\sqrt{3+\sqrt{5}}\right).\sqrt{2}+2\sqrt{5}\)
Rút gọn:
A = \(\sqrt{2}\left(\sqrt{8}-\sqrt{32}-2\sqrt{18}\right)\)
B = \(\left(\sqrt{2}-\sqrt{3-\sqrt{5}}\right)\)
C = \(\sqrt{4-\sqrt{7}}-\sqrt{4+\sqrt{7}}\)
D = \(\sqrt{3}-\sqrt{2}-\sqrt{\sqrt{3}+\sqrt{2}}\)
E = \(\left(\sqrt{2}-\sqrt{3}+\sqrt{5}\right)\sqrt{2}+2\sqrt{5}\)
F = \(\left(\sqrt{14}-\sqrt{10}\right)\left(\sqrt{6+\sqrt{35}}\right)\)
G = \(\sqrt{11-4\sqrt{7}}-\sqrt{2}\times\sqrt{8+3\sqrt{7}}\)
Thực hiện phép tính:
a) \(\left(2\sqrt{2}-\sqrt{3}\right)^2\)
b) \(\left(1+\sqrt{3}-\sqrt{2}\right)\left(1+\sqrt{3}+\sqrt{2}\right)\)
c) \(\left(\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\right)^2\)
d) \(\left(\sqrt{\sqrt{11}+\sqrt{7}}-\sqrt{\sqrt{11}-\sqrt{7}}\right)^2\)
e) \(\sqrt{2+\sqrt{3}}-\sqrt{2-\sqrt{3}}\)
f) \(\sqrt{21-12\sqrt{3}}-\sqrt{3}\)
g) (\(\sqrt{6}+\sqrt{2}\))(\(\sqrt{3}-2\))\(\sqrt{\sqrt{3}+2}\)
h) \(\sqrt{6-2\sqrt{\sqrt{2}+\sqrt{12}+\sqrt{18-\sqrt{128}}}}\)
Mọi người làm giúp em gấp với !!!!!!!!!!!!!!!!!
A)\(\sqrt{2-\sqrt{3}}.\left(\sqrt{6}+\sqrt{2}\right)\)
B)\(\left(\sqrt{2}+1^{ }\right)^3-\left(\sqrt{2}-1\right)^3\) C)\(\dfrac{2\sqrt{8}-\sqrt{12}}{\sqrt{18}-\sqrt{48}}-\dfrac{\sqrt{5}+\sqrt{27}}{\sqrt{30}+\sqrt{162}}\) D)\(\sqrt{\dfrac{2-\sqrt{3}}{2+\sqrt{3}}}+\sqrt{\dfrac{2+\sqrt{3}}{2-\sqrt{3}}}\) E)\(\dfrac{\sqrt{3-\sqrt{5}}.\left(3+\sqrt{5}\right)}{\sqrt{10}+\sqrt{2}}\) F)\(\dfrac{1}{\sqrt{2}+\sqrt{2+\sqrt{3}}}+\dfrac{1}{\sqrt{2}-\sqrt{2-\sqrt{3}}}\)
