Question

Bài 1: Phân tích đa thức thành nhân tử:

a. \(x^3+2x-3\)

b. \(x^3+5x^2+8x+4\)

f. \(x^3-x^2-x-2\)

c. \(x^3-7x+6\)

d. \(x^3-9x^2+6x+16\)

e. \(x^3-x^2-4\)

Answer 1

Khó câu f với câu e

Answer 2

f) x³-x²-x-2

= x³-2x²+x²-2x+x-2

= x²(x-2)+x(x-2)+(x-2)

= (x-2)(x²+x+1)

e)

x³-x²-4

= x³-2x²+x²-2x+2x-4

= x²(x-2)+x(x-2)+2(x-2)

= (x-2)(x²+x+2)

Answer 3

a]=x³-x²+x²-x+3x-3

=x²(x-1)+x(x-1)+3(x-1)

=(x-1)(x²+x+3)

b]=x³+x²+4x²+4x+4x+4

=x²(x+1)+4x(x+1)+4(x+1)

=(x+1)(x²+4x+4)

=(x+1)(x²+2x+2x+4)

=(x+1)[x(x+2)+2(x+2)]

=(x+1)(x+2)(x+2)

f)=x³-2x²+x²-2x+x-2

=x²(x-2)+x(x-2)+(x-2)

=(x-2)(x²+x+1)

c)=x³+3x²-3x²-9x+2x+6

=x²(x+3)-3x(x+3)+2(x+3)

=(x+3)(x²-3x+2)

=(x+3)(x²-2x-x+2)

=(x+3)[x(x-2)-(x-2)]

=(x+3)(x-2)(x-1)

d)=x³-2x²-7x²+14x-8x+16

=x²(x-2)-7x(x-2)-8(x-2)

=(x-2)(x²-7x-8)

=(x-2)(x²+8x-x-8)

=(x-2)[x(x+8)-(x+8)]

=(x-2)(x+8)(x-1)

e)=x³-2x²+x²-2x+2x-4

=x²(x-2)+x(x-2)+2(x-2)

=(x-2)(x²+x+2)

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