Question

a)x^2-4x+3

b)2x^3+x-2x^2-1

c)25x^2-9

d)4y^2+4y-9x^2+1

Answer 1

Đề là phân tích thành nhân tử hở bạn

Answer 2

https://i.imgur.com/9Kjp6r0.jpg

Answer 3

a)\(x^2-4x+3=x^2-3x-x+3=x\left(x-3\right)-\left(x-3\right)\)

=(x-1)(x-3)

b)\(2x^3+x-2x^2-1=x\left(2x^2+1\right)-\left(2x^2+1\right)\)

<=>(x-1)\(\left(2x^2+1\right)\)

c)\(25x^2-9=\left(5x-3\right)\left(5x+3\right)\)

d)\(4y^2-9x^2+4y+1=4y^2+4y+1-9x^2\)

=(2y+1)²-9x²=(2y+1-3x)(2y+1+3x)