a: \(A=\left(\dfrac{a-1}{2\sqrt{a}}\right)^2\cdot\dfrac{a-2\sqrt{a}+1-a-2\sqrt{a}-1}{a-1}\)
\(=\dfrac{\left(a-1\right)^2}{4a}\cdot\dfrac{-4\sqrt{a}}{a-1}=\dfrac{-\left(a-1\right)}{\sqrt{a}}\)
b: Để A<0 thì -(a-1)<0
=>a-1>0
=>a>1
c: Để A=-2 thì \(-\left(a-1\right)=-2\sqrt{a}\)
=>a-1-2 căn a=0
=>căn a=1+căn 2
hay \(a=3+2\sqrt{2}\)