a: Khi x=36 thì \(B=\dfrac{6-3}{6+1}=\dfrac{3}{7}\)
b: ĐKXĐ: x>=0; x<>9
\(A=\dfrac{2x-6\sqrt{x}+x+4\sqrt{x}+3+11\sqrt{x}-3}{x-9}=\dfrac{3x+9\sqrt{x}}{x-9}=\dfrac{3\sqrt{x}}{\sqrt{x}-3}\)
c: \(P=A\cdot B=\dfrac{3\sqrt{x}}{\sqrt{x}+1}=3-\dfrac{3}{\sqrt{x}+1}\)
P nguyên khi \(\sqrt{x}+1\in\left\{1;3\right\}\)
=>x=0 hoặc x=4