Question

\(A=\frac{1}{ab}\cdot\frac{\sqrt{a^2b^4}}{4}\)(a<0;b khác 0)

\(B=\frac{\left(a-3\right)^2}{2}\cdot\sqrt{\frac{25}{a^2-6a+9}}\)(a<3)

Answer 1

A= \(\frac{1}{ab}\). \(\frac{|ab^2|}{4}\)

Vì a<0 nên \(\left|ab^2\right|\)= -a\(b^2\) => A= -b/4

Answer 2

\(A=\frac{1}{ab}.\frac{\left|a\right|b^2}{4}=\frac{1}{a}.\frac{-ab}{4}=\frac{-b}{4}\)

\(B=\frac{\left(a-3\right)^2}{2}.\frac{5}{\left|3-a\right|}=\frac{\left(a-3\right)^2}{2}.\frac{-5}{a-3}=\frac{-5\left(a-3\right)}{2}\)