Question

a)1/3 + 3/4 ( 2x - 2 ) = -6

b) (x. 6 \(\dfrac{2}{7}\)+ 3/7) . 2 \(\dfrac{1}{5}\) - 3/7 = -2

c) x/5 + 9/2 - 6/7 : 36/49

d) 17/2 - \(\left|2x-\dfrac{3}{4}\right|\) _\(\dfrac{7}{4}\)

e) \(\left(2x+\dfrac{3}{5}\right)^2\) - 9/ 25 = 0

Giúp mình với mình cần gấp

Answer 1

a: \(\Leftrightarrow\left(2x-2\right)\cdot\dfrac{3}{4}=-6-\dfrac{1}{3}=-\dfrac{19}{3}\)

\(\Leftrightarrow2x-2=-\dfrac{19}{3}:\dfrac{3}{4}=-\dfrac{76}{9}\)

=>2x=-58/9

hay x=-29/9

b: \(\Leftrightarrow\left(\dfrac{44}{7}x+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)

\(\Leftrightarrow x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{5}{7}\)

\(\Leftrightarrow x\cdot\dfrac{44}{7}=-\dfrac{8}{7}\)

hay x=-2/11

e: \(\left(2x+\dfrac{3}{5}\right)^2=\dfrac{9}{25}\)

\(\Leftrightarrow\left[{}\begin{matrix}2x+\dfrac{3}{5}=\dfrac{3}{5}\\2x+\dfrac{3}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{3}{5}\end{matrix}\right.\)