Bài 2: Nhân đa thức với đa thức
Các câu hỏi tương tự
a)(2-x)(1 2x) (1 x) - (x^4 x^3-5x^2-5)
b) (x^2-7) (x+2) - (2x-1)(x-14)+ x(x^2-2x-22) + 35
Tìm x, biết:
a) 3x(4x-3) - 2x(5-6x) = 0
b) 5(2x-3) + 4x(x-2) + 2x(3-2x) = 0
c) 3x(2-x) + 2x(x-1) = 5x(x+3)
d) 3x(x+1) - 5x(3-x) + 6(x2 + 2x + 3) = 0
Tìm x biết
a) (2x+3)(x–4)+(x–5)(x–2)=(2x+1)(x–4)
b)(8x–3)(3x+2)–(4x+7)(x+4)=(2x+1)(5x–1)
c) 2x^2+3(x–1)(x+1)=5x(x+1)
d) (8–5x)(x+2)+4(x–2)(x+1)+(x–2)(x+2)
e)4(x–1)(x+5)–(x+2)(x+5)=3(x–1)(x+2)
Thực hiện các phép tính sau:
a) (x2 -1) (x2 + 2x)
b) (2x-1)(3x+2)(3-x)
c) (x+3)(x2 + 3x-5)
d) (x+1)(x2 - x+1)
e) (2x3 - 3x-1)(5x+2)
f) (x2 - 2x+3)(x-4)
g) (4x-1)(3x+1)-5x(x-3)-(x-4)(x-3)
h) (5x-2)(x+1)-3x(x2-x-3)-2x(x-5)(x-4)
Tìm x:
a, 3.(2x-1).(3x-1)-(2x-3).(9x-1)-3=-3
b, (3x-1).(2x+7)-(x+1).(6x-5)=(x+2)-(x-5)
c, (6x-2)2+(5x-2)2-4.(3x-1).(5x-2)=0
d, (x+3)2-(x-4).(x+8)=1
e, 3.(x+2)2+(2x-1)2-7.(x+3).(x-3)=36
Rút gọn:
A=(2x-1)(x+3)-(x-2)(3x-4)+5x
B=5x(2x²-3x+1)-2x(x+1)(x-2)
C=(3x+2)(x-1)-2x(x+3)-2x+1
Giúp mk nha mk đang cần gấp
Thanks!
a/ (3x-5)(2x+1)-6x(x-2)-5x+19
b/ (x+5)(x2-5x+25)-x(x2-4x)-(2x+3)(2x-3)
1. (2x +3) (x- 5) +(X-4 ) + (x-5) ( x-2 0 = (3x -5) ( x-4)
2. (8x-3) (3x +2) - (4x+ 7) (x+4) = (2x + 1) (5x-1)
3. 2x^2 + (x -1) (x+1)= 5x (x+10
4. 4- ( x-1) (x+5) - (x+2) (x+5) = 3(x-1) (x+2)
a, A = (5x-2) × (x+1) - ( x-3) × (5x+1) - 17( x+3)
b, B = (6x-5) × ( x+8) - (3x-1) × (2x+3) - 9(4x-3)
c, C = x(x^3 + x^2 - 3x -2 ) - ( x^2 -2 ) × ( x^2+x -1 )