Question

A) (X-3/5)^2=64

B) x/4=y/6, y/2=z/3 và y+x+z= 121

Answer 1

a) (\(x-\dfrac{3}{5}\))\(^2\)=64

=> \(x-\dfrac{3}{5}\)=\(\sqrt{64}\)

=> \(x-\dfrac{3}{5}\) =8 hoặc \(x-\dfrac{3}{5}\)=-8

Trường hợp 1:

\(x-\dfrac{3}{5}\) = 8=>\(x\) =\(8+\dfrac{3}{5}\)=>\(x\)=\(\dfrac{43}{5}\)

Trường hợp 2:

\(x-\dfrac{3}{5}\)=\(-8\)=>\(x\)=\(-8+\dfrac{3}{5}\)=>\(x=-\dfrac{37}{5}\)

Answer 2

b: y/2=z/3 nên y/6=z/9

=>x/4=y/6=z/9=(x+y+z)/(4+6+9)=121/19

=>x=484/19; y=726/19; z=1089/19