\(\left(8+2\dfrac{1}{3}-\dfrac{3}{5}\right)-\left(5+0,4\right)-\left(3\dfrac{1}{3}-2\right)\)
\(\left(8+\dfrac{7}{3}-\dfrac{3}{5}\right)-\left(5+\dfrac{2}{5}\right)-\left(\dfrac{10}{3}-2\right)\)
\(=\dfrac{120+35-9}{15}-\dfrac{25+2}{5}-\dfrac{10-6}{3}\)
\(=\dfrac{146}{15}-\dfrac{27}{5}-\dfrac{4}{3}\)
\(=\dfrac{146}{15}-\dfrac{81}{15}-\dfrac{20}{15}\)
\(=\dfrac{146-81-20}{15}=\dfrac{45}{15}=3\)