\(\dfrac{6}{x-3\sqrt{x}}\cdot\dfrac{6}{x-9}=\dfrac{6\cdot6}{\left(x-3\sqrt{x}\right)\left(x-9\right)}\)
\(=\dfrac{36}{\sqrt{x}\left(\sqrt{x}-3\right)^2\cdot\left(\sqrt{x}+3\right)}\)
\(\dfrac{6}{x-3\sqrt{x}}\cdot\dfrac{6}{x-9}\) (sửa đề)
\(=\dfrac{6}{\sqrt{x}\left(\sqrt{x}-3\right)}\cdot\dfrac{6}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\)
\(=\dfrac{36}{\sqrt{x}\left(\sqrt{x}-3\right)^2\left(\sqrt{x}+3\right)}\)