`(3x-2)^2 - (2x+3)^2 = 0`
`<=> (3x-2-2x-3)(3x-2+2x+3) = 0`
`<=> (x-5)(5x+1) = 0`
`<=> x = 5` hoặc `x = -1/5`.
=>(3x-2-2x-3)(3x-2+2x+3)=0
=>(x-5)(5x+1)=0
=>x=-1/5 hoặc x=5
(x-3)(2x+1)(4-5x)=0
2x3-5x2+3x=0
(x-3)2=(2x+1)
(3x-1)(x2+2)=(3x-1)(7x-10)
giải phương trình sau
2, (x+3)(x+5)+(x+3)(3x-4)=0
3, (x+6)(3x-1)+x+6=0
4, (x+4)(5x+9)-x-4=0
5, (1-x)(5x+3)=(3x-7)(x-1)
6, 2x(2x-3)=(3-2x)(2-5x)
Tìm x, biết:
a) 7x2 - 28 = 0
b) \(\dfrac{2}{3}\)x(x2 - 4) = 0
c) 2x(3x - 5) - (5 - 3x) = 0
d) (2x - 1)2 - 25 = 0
Giải các pt sau = cách đưa về pt tích:
a,(3x-1)(5x+3)=(2x+3)(3x-1)
b,9x2 -1=(3x+1)(2x-1)
c,(4x-3)2 = 4(x2-2x+1)
d,2x3 +5x2 -7=0
A)X-2/2x-2<1/2
B)3x^2-x-10=0
C) x+1/2x-3>1
Câu 3. Giải các phương trình sau bằng cách đưa về dạng ax+b= 0
1. a, 3x-2=2x-3; b, 3-4y+24+6y=y+27+3y
c, 7-2x=22-3x; d, 8x-3=5x+12
e, x-12+4x=25+2x-1; f, x+2x+3x-19=3x+5
g, 11+8x-3=5x-3+x; h, 4-2x+15=9x+4-2
2. a, 5-(x-6)=4(3-2); b, 2x (x+2)2-8x2=2(x-2) (x2+2x-4)
c, 7-(2x+4)=-(x+4); d, (x-2)3+(3x-1) (3x+1)=(x+1)3
e, (x+1) (2x-3)=(2x-1) (x+5); f, (x-1)3-x(x+1)2=5x (2-x)-11 (x+2)
g, (x-1)-(2x-1)=9-x; h, (x-3) (x+4)-2(3x-2)=(x-4)2
i, x(x+3)2-3x=(x+2)3+1; j, (x+1) (x2-x+1)-2x=x(x+1) (x-1)
3. a, 1,2-(x-0,8)=-2(0,9+x); b, 3,6-0,5 (2x+1)=x-0,25 (2-4x)
c, 2,3x-2 (0,7+2x)= 3,6-1,7x; d, 0,1-2 (0,5t-0,1)=2 (t-2,5)-0,7
e, 3+2,25x+2,6= 2x+5+0,4x; f, 5x+3,48-2,35x= 5,38-2,9x+10,42
giải các phương trình sau:
a)5-(x-6)=4(3-2x) b)\(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=2x+\dfrac{5}{3}\)
c)\(\dfrac{5x+2}{6}-\dfrac{8x-1}{3}=\dfrac{4x+2}{5}-5\) e)\(x-\dfrac{2x-5}{5}+\dfrac{x+8}{6}=7-\dfrac{x-1}{3}\)
d)x2-5x+6=0 f)(x2-4)-(x-2)(3-2x)=0 g)(2x+5)2=(x+2)2
Bài 1. giải các phương trình sau
a/ \(x^2-2x+1\)
b/ \(1+3x+3x^2+x^3=0\)
c/ \(x+x^4\) =0
d/ \(x^3-3x^2+3x-1+2\left(x^2-x\right)=0\)
e/ \(x^2+x-12=0\)
f/ \(6x^2-11x-10=0\)
Cho Q= (2x/x+3 + x/x-3 - 3x2+3/x2+9):(2x-2/x-3 - 1)
tìm gtnn của Q khi x>=0
tìm x biết:
a)x2 + 3x = 0 b) x3 – 4x = 0
c) 5x(x-1) = x-1 d) 2(x+5) - x2-5x = 0
e) 2x(x-5)-x(3+2x)=26 f) 5x.(x – 2012) – x + 2012 = 0
