3-m: 81= 27
=> 3-m= 33. 34
=> 3-m= 37
=> -m= 7
=> m= -7
Vậy m= -7
\(3^{-m}.81=27\)
\(\Rightarrow3^{-m}.3^4=3^3\)
\(\Rightarrow3^{-m}=3\)
\(\Rightarrow-m=1\)
\(\Rightarrow m=-1\)
3^-m:81=27
=>3^-m:3^4=3^3
=>3^-m=3^3.3^4
=>3^-m=3^7
=>m=7
3-m: 81= 27
=> 3-m= 33. 34
=> 3-m= 37
=> -m= 7
=> m= -7
Vậy m= -7
\(3^{-m}.81=27\)
\(\Rightarrow3^{-m}.3^4=3^3\)
\(\Rightarrow3^{-m}=3\)
\(\Rightarrow-m=1\)
\(\Rightarrow m=-1\)
3^-m:81=27
=>3^-m:3^4=3^3
=>3^-m=3^3.3^4
=>3^-m=3^7
=>m=7
Find m: \(\frac{3^{-m}}{81}=27\)
Tính \(\frac{3^{-m}}{81}\)=27
Tìm x :
27 mũ x phần 3 mũ x = 81
Tìm x :
a, \(3^x=9^{-6}.27^{-5}81^8\)
Tìm x:
a) 27x .9x = 927:81
b)\(\left(\dfrac{12}{25}\right)^x=\left(\dfrac{5}{3}\right)^{-2}-\left(\dfrac{-3}{5}\right)^4\)
ind such that
.
Answer:
Tìm x
a) 8<\(2^x\le2^9.2^{-5}\) b) 27<\(81^3:3^x< 243\)
1)tìm x
a)\(\dfrac{x}{12}-\dfrac{5}{6}=\dfrac{1}{12}\)
b)\(\dfrac{\left(-3\right)^x}{81}=-27\) KQ:7
bài 6 : tìm x :
câu 9, \(3^x=9^{-6}.27^{-5}.81^8\)
câu 18, \(4^{x+3}-3.4^{x+1}=13.4^{11}\)