Question

2x^2-4x+2=0

Answer 1

\(2x^2-4x+2=0\)

\(\Rightarrow2.\left(x^2-2x+1\right)=0\)

\(\Rightarrow2.\left(x-1\right)^2=0\)

Vì \(2>0.\)

\(\Rightarrow\left(x-1\right)^2=0\)

\(\Rightarrow x-1=0\)

\(\Rightarrow x=0+1\)

\(\Rightarrow x=1\)

Vậy \(x=1.\)

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Answer 2

\(2x^2-4x+2=0\)

\(\Leftrightarrow2\left(x^2-2x+1\right)=0\)

\(\Leftrightarrow2\left(x-1\right)^2=0\)

\(\Rightarrow\left(x-1\right)^2=0\)

\(\Leftrightarrow x-1=0\)

\(\Leftrightarrow x=1\)