Question

[2.x-3].[3/4.x+1]=0

Answer 1

\(\left(2x-3\right)\left(\dfrac{3}{4}x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-3=0\\\dfrac{3}{4}x+1=0\end{matrix}\right.\) 

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{-4}{3}\end{matrix}\right.\)

Answer 2

`(2x-3)(3/4x+1)=0`

`=>[(2x-3=0),(3/4x+1=0):}`

`=>[(2x=3),(3/4x=-1):}`

`=>[(x=3/2),(x=-4/3):}`

Vậy `x in {3/2;-4/3}`

Answer 3

[2.x-3].[3/4.x+1]=0

<=> 2x-3=0 hoặc 3/4x+1=0

2x-3=0

=>X=3/2

3/4x+1=0

=>3/4x=-1

=>X=-4/3

Vậy x thuộc {3/2;-4/3}