\(\left(2x-1\right)^3=-27\)
\(\left(2x-1\right)^3=\left(-3\right)^3\)
\(\Rightarrow2x-1=-3\)
\(\Rightarrow2x=-3+1\)
\(2x=-2\)
\(x=-2:2\)
\(x=-1\)
Vậy x = - 1
\(\left(2x-1\right)^3=27\)
\(\Leftrightarrow\left(2x-3\right)=\sqrt[3]{27}\)
\(\Leftrightarrow\left(2x-3\right)=3\)
\(\Leftrightarrow2x=6\)
\(\Leftrightarrow x=3\)
(2x-1)^3=-27; -27=(-3)^3
nên 2x-1=-3
2x =-2
x =-1
\(\left(2x-1\right)^3=27\)
\(\left(2x-1\right)^3=3^3\)
\(\Rightarrow2x-1=3\)
\(2x=3+1\)
\(2x=4\)
\(x=4:2\)
\(x=2\)
Vậy \(x=2\)
( 2x - 1 )^3 = -27
( 2x - 1 )^3 = ( -3 )^3
=> 2x - 1 = -3
=> 2x = -3 + 1
2x = -2
x = -2 : 2
x = -1
Vậy x = -1