\(\left(2,5-3x\right):1\dfrac{2}{3}=\left(\dfrac{8}{5}+2x\right):\left(-\dfrac{8}{17}\right)\)
\(\Rightarrow\dfrac{7,5-9x}{5}=\dfrac{-27,2-34x}{8}\)
\(\Rightarrow60-72x=-217,6-272x\)
\(\Rightarrow-200x=277,6\)
\(\Rightarrow x=-\dfrac{347}{250}\)
Vậy \(x=-\dfrac{347}{250}\)
\(\left|2x+3\right|+\left|2x-1\right|=\dfrac{8}{3.\left(x+1\right)^2+2}\)\(\sqrt{ }\)\(\left|2x+3\right|+\left|2x-1\right|\)=\(\dfrac{8}{3.\left(x+1\right)^2+2}\)
1) \(\dfrac{-5}{\dfrac{12}{\left|\dfrac{2}{3}x+\dfrac{1}{2}\right|}}\)= \(\dfrac{\dfrac{-4}{9}}{\dfrac{8}{15}}\)
2) \(\dfrac{\left|3x-5\right|}{-3}\)= \(\dfrac{\dfrac{-5}{6}}{\dfrac{4}{9}}\)
Tìm \(x\) trong các tỉ lệ thức sau :
a) \(3,8:\left(2x\right)=\dfrac{1}{4}:2\dfrac{2}{3}\)
b) \(\left(0,25x\right):3=\dfrac{5}{6}:0,125\)
c) \(0,01:2,5=\left(0,75x\right):0,75\)
d) \(1\dfrac{1}{3}:0,8=\dfrac{2}{3}:\left(0,1x\right)\)
tìm x
(2,5-3x):\(1\dfrac{2}{3}\)= (\(\dfrac{5}{8}\)+2x) : (\(\dfrac{-8}{17}\))
tìm x ∈ Q biết : \(\dfrac{3\left(x+1\right)}{2}\)=\(\dfrac{8}{27\left(x-1\right)}\)
1.Tính
a) 5 - \(\left(-\dfrac{15}{11}\right)^0+\left(\dfrac{1}{3}\right)^2:3\)
b) \(2^3+3.\left(\dfrac{1}{2}\right)^0+[\left(-2\right)^2:\dfrac{1}{2}].8\)
2.Tính giá trị biểu thức
a) \(\dfrac{6^3+3.6^2+3^3}{-13}\)
GIÚP MÌNH VỚI NHA CHIỀU NAY MÌNH PHẢI NỘP RỒI
tính
a, \(\left(\dfrac{5}{3}-\dfrac{1}{2}\right):\left(\dfrac{3}{4}-\dfrac{5}{2}\right)\)
b,\(\left(\dfrac{1}{6}+\dfrac{1}{3}\right)^2\cdot\left(1+\dfrac{2}{3}-\dfrac{5}{4}\right)\)
c, \(\dfrac{4^{30}\cdot3^{43}}{2^{57}\cdot27^{15}}\)
Tìm x, biết :
\(a.3\dfrac{4}{5}:40\dfrac{8}{15}=0,25:x\)
\(b.\left(x+1\right):\dfrac{5}{6}=20:3\)
\(c.\dfrac{7}{x-1}=\dfrac{x+1}{9}\)
tim x
a, \(2,75\div x=0,4\div1,5\)
b, \(3\dfrac{1}{2}\div\left(2x-3\right)=\dfrac{-3}{4}\div0,2\)
c, \(\dfrac{3x+2}{27}=\dfrac{3}{3x+2}\)
d ,\(\dfrac{5-x}{4}=\dfrac{2x+3}{2}\)
giup minh nhe minh dang can gap
