Bài 7: Tỉ lệ thức
Các câu hỏi tương tự
(2,5 - 3x) : \(1\dfrac{2}{3}=\left(\dfrac{8}{5}+2x\right):\left(-\dfrac{8}{17}\right)\)
tìm x
(2,5-3x):\(1\dfrac{2}{3}\)= (\(\dfrac{5}{8}\)+2x) : (\(\dfrac{-8}{17}\))
Tìm x:
1) dfrac{1,2}{30}dfrac{3x+4}{50}
2) dfrac{x-1}{x-5}dfrac{6}{7}
3) dfrac{x-1}{3}dfrac{x+3}{5}
4) dfrac{3}{7}dfrac{2x+1}{3x+5}
5) dfrac{2x+3}{3x+1}dfrac{3}{4}
6) dfrac{2x+3}{6}dfrac{7x-3}{15}
7) dfrac{6x-5}{-7}dfrac{5x-3}{-5}
8) dfrac{x+1}{x-2}dfrac{3}{4}
9) dfrac{2x-3}{x+1}dfrac{4}{7}
10) dfrac{2x+3}{7}dfrac{4x-1}{15}
11) dfrac{2x+3}{24}dfrac{3x-1}{32}
12) dfrac{2x+4}{7}dfrac{4x-2}{15}
13) dfrac{11x-2}{7x+5}dfrac{11}{8}
14) dfrac{12-7x}{-13}dfrac{4-3x}{-5}
15) dfrac{52}{2x-1...
Đọc tiếp
Tìm x:
1) \(\dfrac{1,2}{30}\)\(=\dfrac{3x+4}{50}\)
2) \(\dfrac{x-1}{x-5}\)\(=\dfrac{6}{7}\)
3) \(\dfrac{x-1}{3}\)\(=\dfrac{x+3}{5}\)
4) \(\dfrac{3}{7}\)\(=\dfrac{2x+1}{3x+5}\)
5) \(\dfrac{2x+3}{3x+1}\)\(=\dfrac{3}{4}\)
6) \(\dfrac{2x+3}{6}\)\(=\dfrac{7x-3}{15}\)
7) \(\dfrac{6x-5}{-7}\)\(=\dfrac{5x-3}{-5}\)
8) \(\dfrac{x+1}{x-2}\)\(=\dfrac{3}{4}\)
9) \(\dfrac{2x-3}{x+1}\)\(=\dfrac{4}{7}\)
10) \(\dfrac{2x+3}{7}\)\(=\dfrac{4x-1}{15}\)
11) \(\dfrac{2x+3}{24}\)\(=\dfrac{3x-1}{32}\)
12) \(\dfrac{2x+4}{7}\)\(=\dfrac{4x-2}{15}\)
13) \(\dfrac{11x-2}{7x+5}\)\(=\dfrac{11}{8}\)
14) \(\dfrac{12-7x}{-13}\)\(=\dfrac{4-3x}{-5}\)
15) \(\dfrac{52}{2x-1}\)\(=\dfrac{13}{30}\)
1,2x :dfrac{5}{7}dfrac{14}{15} : dfrac{3}{2}
2,dfrac{9}{10} :(3x) dfrac{5}{3}:dfrac{20}{27}
3,dfrac{x-2}{27}dfrac{3}{x-2}
4,dfrac{2x+5}{9-2x}dfrac{2}{5}
5,dfrac{x-7}{x+8}dfrac{x-8}{x+9}
Đọc tiếp
1,2x :\(\dfrac{5}{7}\)=\(\dfrac{14}{15}\) : \(\dfrac{3}{2}\)
2,\(\dfrac{9}{10}\) :(3x) = \(\dfrac{5}{3}:\dfrac{20}{27}\)
3,\(\dfrac{x-2}{27}=\dfrac{3}{x-2}\)
4,\(\dfrac{2x+5}{9-2x}=\dfrac{2}{5}\)
5,\(\dfrac{x-7}{x+8}=\dfrac{x-8}{x+9}\)
Tìm x,y,z biết:
A)o,3:3và 1/3 = 6 : 15 b:x/-36 =5/6 c)x/6 = y/5 và x-y = -28 d)x/2 = y/7 và 2x-5y = 93
E)2 và 2/3 :x =1 và 7/9 : 0.02 ;f)x/5 = y/4:x2-y2=36 ;g)x : 9-3,7) = (-2,5) :0,25 : H)x/3 = y/4;y/3=z/5 và 2x-3y+z = 6 I)X/7 = y/-9 =z/3 và 3x-5y =156
\(\left|2x+3\right|+\left|2x-1\right|=\dfrac{8}{3.\left(x+1\right)^2+2}\)\(\sqrt{ }\)\(\left|2x+3\right|+\left|2x-1\right|\)=\(\dfrac{8}{3.\left(x+1\right)^2+2}\)
Bài 1: Tìm x biết
a) dfrac{5}{6} : x 30:3
b) x : 2,5 0,003:0,75
c) 3,8 : (2x) dfrac{1}{4} : 2dfrac{2}{3}
d) dfrac{2}{3} : 0,4 x : dfrac{4}{5}
f) 3dfrac{4}{5} : 40dfrac{8}{15} 0,25 : x
e) dfrac{x}{-15} dfrac{-60}{x}
Đọc tiếp
Bài 1: Tìm x biết
a) \(\dfrac{5}{6}\) : x = 30:3
b) x : 2,5 = 0,003:0,75
c) 3,8 : (2x) = \(\dfrac{1}{4}\) : 2\(\dfrac{2}{3}\)
d) \(\dfrac{2}{3}\) : 0,4 = x : \(\dfrac{4}{5}\)
f) 3\(\dfrac{4}{5}\) : 40\(\dfrac{8}{15}\) = 0,25 : x
e) \(\dfrac{x}{-15}\) = \(\dfrac{-60}{x}\)
bài tìm x,y,z biết :a)\(\dfrac{x}{5}=\dfrac{y}{6};\dfrac{y}{8}=\dfrac{z}{7}\)và x+y-z=69
b)\(\dfrac{x}{3}=\dfrac{y}{4};\dfrac{y}{3}=\dfrac{z}{5}\)và 2x-3y+z=6
c)\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{z}{6}\)và x+y=14
d)\(\dfrac{2}{3x}=\dfrac{1}{2y}=\dfrac{2}{z}\)và 3x+2y+z=1
\(\dfrac{x}{3}\)=\(\dfrac{y}{8}\)=\(\dfrac{z}{5}\) và 2x + 3y - z = 50