\(\dfrac{1}{2}x-\dfrac{1}{3}x=\dfrac{-1}{3}\\ x\cdot\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=\dfrac{-1}{3}\\ x\cdot\dfrac{1}{6}=\dfrac{-1}{3}\\ x=\dfrac{-1}{3}:\dfrac{1}{6}\\ x=\dfrac{-2}{3}\)
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