Ta có:
\(\frac{1}{2}-\left(\frac{1}{3}+\frac{1}{4}\right)\)
\(=\frac{1}{2}-\frac{7}{12}\)
\(=-\frac{1}{12}.\)
\(\frac{1}{48}-\left(\frac{1}{16}-\frac{1}{6}\right)\)
\(=\frac{1}{48}+\frac{5}{48}\)
\(=\frac{1}{8}.\)
=> \(-\frac{1}{12}< x< \frac{1}{8}\)
=> \(x=0.\)
Vậy \(x=0.\)
Chúc bạn học tốt!
1/2 - ( 4/12 + 3/12 ) < x < 1/48 - ( 6/96 - 16/96 )
1/2 - 7/12 < x < 1/48 + 5/48
-1/12 < x < 1/8
Vì -1/12 < 0
1/8 > 0
nên x = 0
Vậy x = 0