xy \(\ge\) 2016x + 2017y
\(\Leftrightarrow\)1 \(\ge\) \(\dfrac{2016}{y}\) + \(\dfrac{2017}{x}\)\(\ge\dfrac{\left(\sqrt{2016}+\sqrt{2017}\right)^2}{x+y}\)
\(\Rightarrow x+y\ge\left(\sqrt{2016}+\sqrt{2017}\right)^2\)
Bài này lâu rùi sao ko mất đi thế ???
Bó tay "
"