\(1,P=\dfrac{\dfrac{x}{6}\cdot x\sqrt{x}\cdot\sqrt[4]{5}}{x\sqrt{x}}=\dfrac{x}{6}\cdot\sqrt[4]{5}\)
1.
Xem lại đề, chỗ \(\sqrt[4]{5}\) trên tử số
2.
\(P=\sqrt[4]{x^2.x\sqrt[]{x\sqrt[4]{x^3}}}:x^{\dfrac{9}{16}}=\sqrt[4]{x^3\sqrt[8]{x^4.x^3}}:x^{\dfrac{9}{16}}=\sqrt[4]{x^3.x^{\dfrac{7}{8}}}:x^{\dfrac{9}{16}}\)
\(=\sqrt[4]{x^{\dfrac{31}{8}}}:x^{\dfrac{9}{16}}=x^{\dfrac{31}{32}}:x^{\dfrac{9}{16}}=x^{\dfrac{31}{32}-\dfrac{9}{16}}=x^{\dfrac{13}{32}}\)