Bài 1 :
Ta có : \(x^2-6x=6\)
=> \(x^2-6x-6=0\)
=> \(x^2-2.3x+9=15\)
=> \(\left(x-3\right)^2=15\)
=> \(x=3\pm\sqrt{15}\)
Vậy ...
Đặt \(x=\sqrt{4+\sqrt{4+\sqrt{4+...+\sqrt{4}}}},x>0\)
=> \(x^2=4+\sqrt{4+\sqrt{4+...+\sqrt{4}}}\)
=> \(x^2-x-4=4+\sqrt{4+\sqrt{4}+...}-\sqrt{4+\sqrt{4+\sqrt{4}+...+\sqrt{4}}}-4=0\)
=> \(x=\frac{1\pm\sqrt{17}}{2}< 3\)
Vậy ...