Đặt HB=a; HC=b
Theo đề, ta có: -a+b=14
=>-a=14-b
=>a=14-b
Ta có: \(ab=24^2=576\)
\(\Leftrightarrow b\left(14-b\right)=576\)
\(\Leftrightarrow b^2-14b-576=0\)
=>b=32
=>BH=18(cm)
\(\dfrac{AB}{AC}=\sqrt{\dfrac{BH}{CH}}=\sqrt{\dfrac{18}{32}}=\dfrac{3}{4}\)
BC=BH+CH=50cm
DB/DC=AB/AC=3/4
=>DB=3/4DC
mà DB+DC+50
nên DB=150/7(cm); DC=200/7(cm)