\(1+\frac{1}{x}=3\)
\(\Rightarrow\frac{1+x}{x}=3\)
\(\Rightarrow1+x=3x\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
\(1+\frac{1}{x}=3\)
\(\Leftrightarrow\frac{1}{x}=3-2\)
\(\Leftrightarrow\frac{1}{x}=1\)
\(\Leftrightarrow x=1\)
Vậy x=1
1+\(\frac{1}{x}\)= 3
<=> \(\frac{1}{x}\) = 3-1
<=> \(\frac{1}{x}\) =2
<=> x = \(\frac{1}{2}\)
Vậy x = \(\frac{1}{2}\)
1 + \(\frac{1}{x}\) = 3
=> \(\frac{x+1}{x}\) = 3
=> x + 1 = 3x
=> x - 3x = -1
=> -2x = -1
=> x = \(\frac{-1}{-2}\) = \(\frac{1}{2}\)
Vậy x = \(\frac{1}{2}\) thì 1 + \(\frac{1}{x}\) = 3
XONG !!![]()
Sửa lại:
\(1+\frac{1}{x}=3\)
\(\Rightarrow\frac{1+x}{x}=3\)
\(\Rightarrow1+x=3x\)
\(\Rightarrow2x=1\)
\(\Rightarrow x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
\(1+\frac{1}{x}=3\)
\(\Leftrightarrow\frac{1}{x}=3-1\)
\(\Leftrightarrow\frac{1}{x}=2\)
\(\Leftrightarrow x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\) để \(1+\frac{1}{x}=3\)
\(\frac{1}{2}\) nha bạn
Thấy ở dưới nhìu cách giải rùi nên mk ko giải tườm tật nữa nha