Bài 1a) 3x - 2 = 2x - 3
<=> 3x - 2x = -3 + 2
<=> x = -1
b) 5 - (x - 6) = 4(3 - 2x)
<=> 5 - x + 6 = 12 - 8x
<=> -x + 8x = 12 - 5 - 6
<=> 7x = 1
<=> x = 1/7
\(c)\dfrac{3}{2}(x-\dfrac{5}{4})-\dfrac{5}{8}=x \\<=> \dfrac{3}{2}x-x=\dfrac{5}{8}+\dfrac{15}{8} \\<=>\dfrac{1}{2}x=\dfrac{5}{2} \\<=>x=5 \\d) \dfrac{10x+3}{12}=1+\dfrac{6+8x}{9} \\<=>\dfrac{30x+9}{36}=\dfrac{36}{36}+\dfrac{24+32x}{36} \)
\(\\<=>-2x=36+24-9 \\<=>-2x=51 \\<=>x=\dfrac{-51}{2}\)
Bài 2: 2.(-2) + k = -2 - 1
<=> k = 1
Bài 3: Xét pt 3x = 3(x + 2) <=> 0x = 6 (vô lí)
--> Pt vô nghiệm
Xét pt 2(x - 1) = 2x <=> 0x = 2 (vô lí)
--> pt vô nghiệm
Vậy 2 pt tương đương.
