\(a,=\dfrac{x+x-1+x+10}{x+3}=\dfrac{3\left(x+3\right)}{x+3}=3\\ b,=\dfrac{5x-6-3x+5}{14x-7}=\dfrac{2x-1}{7\left(2x-1\right)}=\dfrac{1}{7}\\ c,=\dfrac{x^2-18x+6x+36}{6x\left(x-6\right)}=\dfrac{\left(x-6\right)^2}{6x\left(x-6\right)}=\dfrac{x-6}{6x}\\ d,=\dfrac{x^2+xy-3xy+y^2}{xy\left(x-y\right)}=\dfrac{x^2-2xy+y^2}{xy\left(x-y\right)}=\dfrac{\left(x-y\right)^2}{xy\left(x-y\right)}=\dfrac{x-y}{xy}\)
a, \(\dfrac{x+x-1+x+10}{x+3}=\dfrac{3x+9}{x+3}=\dfrac{3\left(x+3\right)}{x+3}=3\)
b, \(\dfrac{5x-6-3x+5}{14x-7}=\dfrac{2x-1}{7\left(2x-1\right)}=\dfrac{1}{7}\)
c, \(\dfrac{x-18}{6\left(x-6\right)}+\dfrac{x+6}{x\left(x-6\right)}=\dfrac{x\left(x-18\right)+6\left(x+6\right)}{6x\left(x-6\right)}=\dfrac{x^2-18x+6x+36}{6x\left(x-6\right)}=\dfrac{x^2-12x+36}{6x\left(x-6\right)}=\dfrac{\left(x-6\right)^2}{6x\left(x-6\right)}=\dfrac{x-6}{6x}\)
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