a,12.x= -36
<=> x = -3.
Vậy...
b,2.|x| =16
<=> |x| = 8
<=> x = { 8;-8}
Vậy...
a, 12.x=-36
x=-36:12
x=-3
vậy x=-3
b,2./x/=16
/x/=16:2
/x/=8
⇒x=-8 ; x= 8
vậy x=-8, x=8
a) Ta có: \(12\cdot x=-36\)
\(\Leftrightarrow x=-36:12\)
\(\Leftrightarrow x=-3\)
Vậy: x=-3
b) Ta có: \(2\cdot\left|x\right|=16\)
\(\Leftrightarrow\left|x\right|=8\)
hay \(x\in\left\{8;-8\right\}\)
Vậy: \(x\in\left\{8;-8\right\}\)