b. \(\Leftrightarrow\left\{{}\begin{matrix}m^2-2=2\\m-1=-3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}m=\pm2\\m=-2\end{matrix}\right.\Leftrightarrow m=-2\)
c. PT hoành độ giao điểm: \(\left(m^2-2\right)x+m-1=2x-3\)
\(\Leftrightarrow\left(m^2-4\right)x=-2-m\\ \Leftrightarrow x=\dfrac{-\left(m+2\right)}{m^2-4}=\dfrac{-\left(m+2\right)}{\left(m+2\right)\left(m-2\right)}=\dfrac{-1}{m-2}\)
Hoành độ nguyên
\(\Leftrightarrow m-2\inƯ\left(-1\right)=\left\{-1;1\right\}\\ \Leftrightarrow m\in\left\{1;3\right\}\left(n\right)\)
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