d) \(\dfrac{\sqrt{2}}{3-2\sqrt{2}}\) = \(\dfrac{\sqrt{2}.\left(3+2\sqrt{2}\right)}{\left(3-2\sqrt{2}\right)\left(3+2\sqrt{2}\right)}\) = \(\dfrac{3\sqrt{2}+4}{3^2-\left(2\sqrt{2}\right)^2}\) = \(\dfrac{3\sqrt{2}+4}{1}\) = \(3\sqrt{2}+4\)
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