Bài 4: Liên hệ giữa phép chia và phép khai phương

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Nguyễn Hoàng Minh
25 tháng 8 2021 lúc 15:54

\(1,4-2\sqrt{3}=\left(\sqrt{3}-1\right)^2\\ 2,\sqrt{7-4\sqrt{3}}=\sqrt{\left(2-\sqrt{3}\right)^2}=2-\sqrt{3}\\ 3,\sqrt{5+2\sqrt{6}}=\sqrt{\left(\sqrt{2}+\sqrt{3}\right)^2}=\sqrt{2}+\sqrt{3}\\ 4,\sqrt{16+6\sqrt{7}}=\sqrt{\left(3+\sqrt{7}\right)^2}=3+\sqrt{7}\\ 5,\sqrt{12+2\sqrt{35}}=\sqrt{\left(\sqrt{7}+\sqrt{5}\right)^2}=\sqrt{7}+\sqrt{5}\\ 6,\sqrt{9-4\sqrt{5}}=\sqrt{\left(\sqrt{5}-2\right)^2}=\sqrt{5}-2\)

Tick plzzz

Nhan Thanh
25 tháng 8 2021 lúc 16:06

1. \(\sqrt{4-2\sqrt{3}}=\sqrt{\left(\sqrt{3}-1\right)^2}=\sqrt{3}-1\)

2. \(\sqrt{7-4\sqrt{3}}=\sqrt{\left(2-\sqrt{3}\right)^2}=2-\sqrt{3}\)

3. \(\sqrt{5+2\sqrt{6}}=\sqrt{\left(\sqrt{3}+\sqrt{2}\right)^2}=\sqrt{3}+\sqrt{2}\)

4. \(\sqrt{16+6\sqrt{7}}=\sqrt{\left(3+\sqrt{7}\right)^2}=3+\sqrt{7}\)

5. \(\sqrt{12+2\sqrt{35}}=\sqrt{\left(\sqrt{7}+\sqrt{5}\right)^2}=\sqrt{7}+\sqrt{5}\)

6. \(\sqrt{9-4\sqrt{5}}=\sqrt{\left(\sqrt{5}-2\right)^2}=\sqrt{5}-2\)

7. \(\sqrt{18-2\sqrt{65}}=\sqrt{\left(\sqrt{13}-\sqrt{5}\right)^2}=\sqrt{13}-\sqrt{5}\)

8. \(\sqrt{27+10\sqrt{2}}=\sqrt{\left(5+\sqrt{2}\right)^2}=5+\sqrt{2}\)

9. \(\sqrt{14+6\sqrt{5}}=\sqrt{\left(3+\sqrt{5}\right)^2}=3+\sqrt{5}\)

10. \(\sqrt{3+2\sqrt{2}}-\sqrt{6-4\sqrt{2}}=\sqrt{\left(1+\sqrt{2}\right)^2}-\sqrt{\left(2-\sqrt{2}\right)^2}=1+\sqrt{2}-2+\sqrt{2}=2\sqrt{2}-1\)

 

 

Nhan Thanh
25 tháng 8 2021 lúc 16:16

11. \(\sqrt{5+2\sqrt{6}}-\sqrt{5-2\sqrt{6}}\)

\(=\sqrt{\left(\sqrt{3}+\sqrt{2}\right)^2}-\sqrt{\left(\sqrt{3}-\sqrt{2}\right)^2}\)

\(=\sqrt{3}+\sqrt{2}-\sqrt{3}+\sqrt{2}=2\sqrt{2}\)  

12. \(\sqrt{3+2\sqrt{2}}+\sqrt{5-2\sqrt{6}}\)

\(=\sqrt{\left(1+\sqrt{2}\right)^2}+\sqrt{\left(\sqrt{3}-\sqrt{2}\right)^2}\)

\(=1+\sqrt{2}+\sqrt{3}-\sqrt{2}=1+\sqrt{3}\)

13. \(\sqrt{9-4\sqrt{5}}+\sqrt{6+2\sqrt{5}}\)

\(=\sqrt{\left(\sqrt{5}-2\right)^2}+\sqrt{\left(\sqrt{5}+1\right)^2}\)

\(=\sqrt{5}-2+\sqrt{5}+1=2\sqrt{5}-1\)

14. \(\sqrt{11+6\sqrt{2}}+\sqrt{6+4\sqrt{2}}-2\sqrt{2}\)

\(=\sqrt{\left(3+\sqrt{2}\right)^2}+\sqrt{\left(2+\sqrt{2}\right)^2}-2\sqrt{2}\)

\(=3+\sqrt{2}+2+\sqrt{2}-2\sqrt{2}=5\)

15. \(\sqrt{15-6\sqrt{6}}+\sqrt{10+4\sqrt{6}}-\sqrt{7+2\sqrt{6}}\)

\(=\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(2+\sqrt{6}\right)^2}-\sqrt{\left(1+\sqrt{6}\right)^2}\)

\(=3-\sqrt{6}+2+\sqrt{6}-1-\sqrt{6}=4-\sqrt{6}\)

16. \(\sqrt{31-8\sqrt{15}}+\sqrt{24-6\sqrt{15}}\)

\(=\sqrt{\left(4-\sqrt{15}\right)^2}+\sqrt{\left(\sqrt{15}-3\right)^2}\)

\(=4-\sqrt{15}+\sqrt{15}-3=1\)

 

Nguyễn Lê Phước Thịnh
26 tháng 8 2021 lúc 0:50

1: \(\sqrt{4-2\sqrt{3}}=\sqrt{3}-1\)

2: \(\sqrt{7-4\sqrt{3}}=2-\sqrt{3}\)

3: \(\sqrt{5+2\sqrt{6}}=\sqrt{3}+\sqrt{2}\)

4: \(\sqrt{16+6\sqrt{7}}=3+\sqrt{7}\)

5: \(\sqrt{12+2\sqrt{35}}=\sqrt{7}+\sqrt{5}\)

6: \(\sqrt{9-4\sqrt{5}}=\sqrt{5}-2\)

7: \(\sqrt{18-2\sqrt{65}}=\sqrt{13}-\sqrt{5}\)

8: \(\sqrt{27+10\sqrt{2}}=5+\sqrt{2}\)

Nguyễn Lê Phước Thịnh
26 tháng 8 2021 lúc 1:00

9: \(\sqrt{14+6\sqrt{5}}=3+\sqrt{5}\)

10: \(\sqrt{3+2\sqrt{2}}-\sqrt{6-4\sqrt{2}}\)

\(=\sqrt{2}+1-2+\sqrt{2}\)

\(=2\sqrt{2}-1\)

11: \(\sqrt{5+2\sqrt{6}}-\sqrt{5-2\sqrt{6}}\)

\(=\sqrt{3}+\sqrt{2}-\sqrt{3}+\sqrt{2}\)

\(=2\sqrt{2}\)

12: \(\sqrt{3+2\sqrt{2}}+\sqrt{5-2\sqrt{6}}\)

\(=\sqrt{2}+1+\sqrt{3}-\sqrt{2}\)

\(=\sqrt{3}+1\)

13: \(\sqrt{9-4\sqrt{5}}+\sqrt{6+2\sqrt{5}}\)

\(=\sqrt{5}-2+\sqrt{5}+1\)

\(=2\sqrt{5}-1\)

14: \(\sqrt{11+6\sqrt{2}}+\sqrt{6+4\sqrt{2}}-2\sqrt{2}\)

\(=3+\sqrt{2}+2+\sqrt{2}-2\sqrt{2}\)

=5

15: \(\sqrt{15-6\sqrt{6}}+\sqrt{10+4\sqrt{6}}-\sqrt{7+2\sqrt{6}}\)

\(=3-\sqrt{6}+\sqrt{6}+2-\sqrt{6}-1\)

\(=4-\sqrt{6}\)

16: \(\sqrt{31-8\sqrt{15}}+\sqrt{24-6\sqrt{15}}\)

\(=4-\sqrt{15}+\sqrt{15}-3\)

=1


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