a) \(\dfrac{-5}{12}+\dfrac{4}{37}+\dfrac{17}{12}-\dfrac{41}{37}\)
⇔ \(\left(\dfrac{-5}{12}+\dfrac{17}{12}\right)+\left(\dfrac{4}{37}-\dfrac{41}{37}\right)\)
⇔ \(1+\left(-1\right)\)
⇔ \(0\)
a) Ta có: \(\dfrac{-5}{12}+\dfrac{4}{37}+\dfrac{17}{12}-\dfrac{41}{37}\)
\(=\left(-\dfrac{5}{12}+\dfrac{17}{12}\right)+\left(\dfrac{4}{37}-\dfrac{41}{37}\right)\)
\(=1-1\)
=0
b) Ta có: \(\dfrac{1}{2}-\dfrac{43}{101}+\left(-\dfrac{1}{3}\right)-\dfrac{1}{6}\)
\(=\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)-\dfrac{43}{101}\)
\(=\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)-\dfrac{43}{101}\)
\(=-\dfrac{43}{101}\)
