HOC24
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Môn học
Chủ đề / Chương
Bài học
`1/3+5/3:x=1/2`
`5/3:x=1/2-1/3`
`5/3:x=1/6`
`x=5/3:1/6`
`x=10`
vậy `x=10`
`A=1+2+2^2+2^3+....+2^2021`
`2A=2+2^2+2^3+....+2^2022`
`=>2A-A=A=2^2022-1`
`P=(2^{10}.3^8+5.4^{5}.3^8)/(2^{10}.27^3-2^10.9^4)`
`P=(2^{10}.3^8+5.2^{10}.3^8)/(2^{10}.3^9-2^{10}.3^8)`
`P=(2^{10}.3^8(1+5))/(2^{10}.3^8(3-1))`
`P=(1+5)/(3-1)=6/2=3`
`a)2023^2023(7^10:7^8-3.2^4-2^2023:2^2023)`
`=2023^2023(7^2-3.2^4-1)`
`=2023^2023(49-48-1)`
`=0`
`b)(2^100+2^101+2^102):(2^97+2^98+2^99)`
`=2^3(2^97+2^98+2^99):(2^97+2^98+2^99)`
`=2^3=8`
`51/57=(3.17)/(3.19)=17/19`
`1717/1919=(101.17)/(101.19)=17/19`
`171717/191919=(10101.17)/(10101.19)=17/19`
`=>51/57=1717/1919=171717/191919`
`1/(-27)=(1/(-x))^3`
`(1/(-3))^3=(1/(-x))^3`
`-3=-x`
`x=3`
Vậy `x=3`
`A=1/3-(x+1)^2`
Vì `(x+1)^2>=0`
`=>1/3-(x+1)^2<=1/3-0=1/3`
Hay `A<=1/3`
Dấu "=" xảy ra khi `x+1=0<=>x=-1`
Vậy `max_A=1/3<=>x=-1`
`(3-x)^3=-27/64`
`(3-x)^3=(-3/4)^3`
`3-x=-3/4`
`x=3+3/4`
`x=15/4`
Vậy `x=15/4`
`A=-4+(x-3)^2`
Vì `(x-3)^2>=0=>A>=-4`
Dấu "=" xảy ra khi `x=3`
vậy `min_A=-4<=>x=3`
`B=1/2-(5x+1)^2`
Vì `(5x+1)^2>=0`
`=>1/2-(5x+1)^2<=1/2`
Dấu "=" xảy ra khi `5x+1=0<=>x=-1/5`
vậy `max_B=1/2<=>x=-1/5`