tia la ze

\(2^{n+3}\)+34=290

\(2^{n+3}\)=290-34

\(2^{n+3}\)=256

\(2^{n+3}\)=\(2^{128}\)

n+3=128

n=128-3=125

vậy n=125 nha bn

2000²

=2000.2000

=4000000

Trả lời: 4000000

\(A=\left|500-x\right|+\left|x-300\right|\ge\left|500-x+x-300\right|=200.\)

A min = 200 khi \(300\le x\le500.\)

A = 1 + 2 + 3 +......+ x = 55 
<=> (1 + 9) + (2 + 8) + (3 + 7) + (4 + 6) + 5 +....+ x = 55 
<=> x = 55 - [(1 + 9) + (2 + 8) + (3 + 7) + (4 + 6) + 5 +....] 
<=> x = 55 - (45 + ...) 
<=> x = 10 - (....) 

=> x = 10