a) \(\dfrac{11\cdot8-11\cdot3}{17-6}\)

\(=\dfrac{11\cdot\left(8-3\right)}{11}=5\)

b) \(\dfrac{24-12\cdot13}{12+4\cdot9}\)

\(=\dfrac{12\cdot\left(2-13\right)}{12\left(1+3\right)}=\dfrac{-11}{4}\)

a: \(=\dfrac{21\cdot11}{22\cdot9}=\dfrac{1}{2}\cdot\dfrac{7}{3}=\dfrac{7}{6}\)

b: \(=\dfrac{49\cdot8}{10}=49\cdot\dfrac{4}{5}=\dfrac{196}{5}\)

c: \(=\dfrac{12\cdot\left(-4\right)}{32\cdot6}=\dfrac{-48}{192}=-\dfrac{1}{4}\)

=21⋅1122⋅9=12⋅73=76

a) \(\dfrac{3x^2+6xy}{6x^2}=\dfrac{3x\left(x+2y\right)}{6x^2}=\dfrac{x+2y}{2x}\)

b) \(\dfrac{2x^2-x^3}{x^2-4}=\dfrac{x^2\left(2-x\right)}{\left(x+2\right)\left(x-2\right)}=\dfrac{-x^2}{x+2}\)

c) \(=\dfrac{x+1}{x^3+1}=\dfrac{x+1}{\left(x+1\right)\left(x^2+x+1\right)}=\dfrac{1}{x^2+x+1}\)

`a, (3x^2+6xy)/(6x^2) = (x+2y)/(3x)`

`b, (2x^2-x^3)/(x^2-4) = (x^2(2-x))/((x-2)(x+2))`

`= -x^2/(x+2)`

`c, (x+1)/(x^3+1) = 1/(x^2-x+1)`

a: 12/21=4/7=8/14

4/56=1/14

b: 12/15=4/5=24/30

6/36=1/6=5/30

15/50=3/10=9/30

c: 63/77=9/11=81/99

60/108=5/9=55/99

-18/27=-2/3=-66/99

d: -26/-156=1/6=7/42

49/-14=-7/2=-147/42

32/112=2/7=12/42

a)      Cách 1:

\(6(y - x) - 2(x - y)\)

\( = 6y - 6x - 2x + 2y\)

\( = 8y - 8x\)

Cách 2:

\(6(y - x) - 2(x - y)\\= 6(y-x)+2(y-x)\\=(6+2).(y-x)\\=8.(y-x)\\=8y-8x\)

b)      \(3{x^2} + x - 4x - 5{x^2}\)

\( = (3{x^2} - 5{x^2}) + (x - 4x)\)

\( =  - 2{x^2} - 3x\)

a: \(=\dfrac{12xy^3z^4}{24x^2y^3z^3}=\dfrac{1}{2}\cdot\dfrac{1}{x}\cdot z=\dfrac{z}{2x}\)

b: \(=\dfrac{3\left(x-2\right)}{6x\left(x-2\right)}=\dfrac{1}{2x}\)

\(a,\dfrac{583}{352}=\dfrac{53}{32}\\ b,\dfrac{121212}{313131}=\dfrac{12}{31}\\ c,\dfrac{153.24-153.11}{160-7}=\dfrac{153\left(24-11\right)}{153}=13\)

a.53/32

b.12/31

c.13

a,434343/343434= 43/34                         b,3625/560= 725/112

a,434343/343434= 43/34                         b,3625/560= 725/112

43/34            725/112

a, =5/14

b, = 1/6

c, = 3/2

d, = 8/7

5/14

1/6

3/2

8/7

a,5/14

b,1/6

c,3/2

d,8/7

A=(-1)+(-1)+...+(-1)+2023

=2023-1011

=1012

1012