= (64+\(\frac{1}{512}\)):512
=(\(\frac{32768}{512}\)+\(\frac{1}{512}\)):512
=\(\frac{32769}{512}\):512=\(\frac{32769}{262144}\)
So sánh 2 biểu thức A và B
a, A=\(\dfrac{10^{15}+1}{10^6+1}\) và B= \(\dfrac{10^6+1}{10^{17}+1}\)
b, C=\(\dfrac{2^{2008}-3}{2^{2007}-1}\) và D=\(\dfrac{2^{2007}+3}{2^{2006}-1}\)
c, M=\(\dfrac{3}{8^3}+\dfrac{7}{8^4}\) và N=\(\dfrac{7}{8^3}+\dfrac{3}{8^4}\)
d, E=\(\dfrac{23^{2000}+3}{23^{2001}+40}\) và F=\(\dfrac{23^{2001}+3}{23^{2002}+40}\)
x2-1/10=23/90
-5/7 . 16\(\dfrac{1}{3}\) + 5/7 . (-23\(\dfrac{2}{3}\))
1) Chứng minh rằng :
a) 817-279+329\(⋮\)33
b) 109+108+107\(⋮\)55
c)\(\dfrac{9^{11}-9^{10}-9^9}{639}\in N\)
d)817-279-913\(⋮\)45
2) Tìm x \(\in\) N*
a)27<3x<3.81
b)415.915<2x.3x<1816.216
c)(2x-1)6=(2x-1)8
Các bạn giúp mình nha 
3/1^2.2^2 + 5/2^2.3^2 + 1/3^2.4^2+....19/9^2.10^2 < 1
(x-2/9)^3=(2/30)^6
(3x^2-51)^2n=(-24)^2n
(8x-1)^2n+1=5^2n+1
1. Tìm x :
x^3 - 1/2 = (-3)/8
(2x - 1)^3 = -8
17 + "3^x" = 98 (3 mũ x nha)
(2x +3)^2 = 9/121
2. Tính
2.1/9 : (1/3)^2 + (201/202)^2018 .(202/201)^2018
giúp mình với ^^
Rút gọn:
a) \(\dfrac{2^{19}\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+2^{10}}\)
b) \(\dfrac{\left(-\dfrac{1}{2}\right)^3-\left(\dfrac{3}{4}\right)^3\cdot\left(-2\right)^2}{2\cdot\left(-1\right)+\left(\dfrac{3}{4}\right)^2-\left(\dfrac{3}{8}\right)}\)
Biết rằng 22+32+42+...+132=818.
Tính A =1^2+3^2+6^2+9^2+12^2+...+39^2
