a)Có NC=NA
\(\Rightarrow ON\perp AC\)
Có \(T\in ON\Rightarrow TA=TC\)(t/c đường trung trực)
Xét \(\Delta TBC\) , có:
\(TB+TC>BC\) (qh 3 cạnh)
\(\Rightarrow TB+TA=BA>BC\)
\(\Rightarrow\stackrel\frown{BA}>\stackrel\frown{BC}\)
b)Có \(OM\perp BC\)(MB=MC); \(OP\perp AB\left(AP=PB\right)\)
Có: AB>BC(cmt)\(\Rightarrow OP< OM\) (K/ cách từ tâm đến dây).
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