ĐK : \(\left\{{}\begin{matrix}x\ge-3\\y\ge-3\end{matrix}\right.\) Đặt : \(\sqrt{x+3}=\sqrt{a}\) , \(\sqrt{y+3}=\sqrt{b}\)
\(\Leftrightarrow\left\{{}\begin{matrix}\sqrt{a}+\sqrt{b}=4\\\sqrt{a+5}+\sqrt{b+5}=6\end{matrix}\right.\)
Giải như bình thường nha bạn !
giải hệ pt: \(\left\{{}\begin{matrix}x+y-\sqrt{xy}=3\\\sqrt{x+1}+\sqrt{y+1}=4\end{matrix}\right.\)
giải hệ: a, \(\left\{{}\begin{matrix}x^2+\frac{1}{y^2}+\frac{x}{y}=3\\x+\frac{1}{y}+\frac{x}{y}=3\end{matrix}\right.\)
b, \(\left\{{}\begin{matrix}\sqrt[]{x-1}+\sqrt[]{y-1}=2\\\frac{1}{x}+\frac{1}{y}=1\end{matrix}\right.\)
c,\(\left\{{}\begin{matrix}x\sqrt[]{x}+y\sqrt[]{y}=35\\x\sqrt[]{y}+y\sqrt[]{x}=30\end{matrix}\right.\)
d,\(\left\{{}\begin{matrix}x^2+xy+y^2=3\\x+xy+y=-1\end{matrix}\right.\)
e,\(\left\{{}\begin{matrix}\left(\frac{x}{y}\right)^3+\left(\frac{x}{y}\right)^2=12\\\left(xy\right)^2+xy=6\end{matrix}\right.\)
Giải hệ phương trình: \(\left\{{}\begin{matrix}\sqrt{x}+\sqrt{6-y}=2\sqrt{3}\\\sqrt{y}+\sqrt{6-x}=2\sqrt{3}\end{matrix}\right.\)
giải hpt:
a)\(\left\{{}\begin{matrix}\dfrac{10}{\sqrt{12x-3}}+\dfrac{5}{\sqrt{4y+1}}=1\\\dfrac{7}{\sqrt{12x-3}}+\dfrac{8}{\sqrt{4y+1}}=1\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{1}{y}=4\\x\left(1+4y\right)+y=2\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}x^2+x+1=3y\\y^2+y+1=3x\end{matrix}\right.\)
giải hệ phương trình: \(\left\{{}\begin{matrix}x^2+2y=xy+4\\x^2-x+3-x\sqrt{6-x}=\left(y-3\right)\sqrt{y-3}\end{matrix}\right.\)
Giải hệ phương trình sau: \(\left\{{}\begin{matrix}2\left(xy+1\right)=x\left(x+y\right)+2\\3xy-x+3=\sqrt{x+2y+1}+\sqrt{x+4y+4}\end{matrix}\right.\)
Giải hệ \(\left\{{}\begin{matrix}9+\left(y-5\right)^2=x+y\\\sqrt{y}-4+x=\frac{\sqrt{x+y}+\sqrt{x+y-9}+2}{\sqrt{y}-x+4}\end{matrix}\right.\)
Giải hệ phương trình:
\(\left\{{}\begin{matrix}\sqrt{x}+\sqrt[4]{32-x}=y^2-3\\\sqrt[4]{x}+\sqrt{32-x}=24-6y\end{matrix}\right.\)
giải hệ pt \(\left\{{}\begin{matrix}x-y=1\left(1\right)\\\sqrt{x^2+2y+3}=3x-5\left(2\right)\end{matrix}\right.\left(x,y\in R\right)}\)
