Đây ko phải dạng vô định, bạn cứ thay số thoải mái thôi
\(=\frac{4}{0}=\infty\)
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Bài 2: Giới hạn của hàm số
Các câu hỏi tương tự
a. limlimits_{xrightarrow0}frac{sqrt{1+2x}-1}{2x} f. limlimits_{xrightarrow1}frac{sqrt{2x+7-3}}{2-sqrt{x+3}}
b. limlimits_{xrightarrow0}frac{4x}{sqrt{9+x}-3} g. limlimits_{xrightarrow0}frac{sqrt{x^2+1}-1}{sqrt{x^2+16}-4}
c. limlimits_{xrightarrow2}frac{sqrt{x+7}-3}{x-2} h. limlimits_{xrightarrow4}frac{sqrt{x+5}-sqrt{2x+1}}{x-4}
d. limlimits_{xrightarrow1}frac{3x-2sqrt{4x^2-x-2}}{x^2-3x+2} k. limlimits...
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a. \(\lim\limits_{x\rightarrow0}\frac{\sqrt{1+2x}-1}{2x}\) f. \(\lim\limits_{x\rightarrow1}\frac{\sqrt{2x+7-3}}{2-\sqrt{x+3}}\)
b. \(\lim\limits_{x\rightarrow0}\frac{4x}{\sqrt{9+x}-3}\) g. \(\lim\limits_{x\rightarrow0}\frac{\sqrt{x^2+1}-1}{\sqrt{x^2+16}-4}\)
c. \(\lim\limits_{x\rightarrow2}\frac{\sqrt{x+7}-3}{x-2}\) h. \(\lim\limits_{x\rightarrow4}\frac{\sqrt{x+5}-\sqrt{2x+1}}{x-4}\)
d. \(\lim\limits_{x\rightarrow1}\frac{3x-2\sqrt{4x^2-x-2}}{x^2-3x+2}\) k. \(\lim\limits_{x\rightarrow0}\frac{\sqrt{x+1}+\sqrt{x+4}-3}{x}\)
e. \(\lim\limits_{x\rightarrow1}\frac{\sqrt{2x+7}+x-4}{x^3-4x^2+3}\)
1, limlimits_{xrightarrow1}frac{2x^2-3x+1}{x^3-x^2-x+1}
2, limlimits_{xrightarrow2}frac{x-sqrt{x+2}}{sqrt{4x+1}-3}
3, limlimits_{xrightarrow0}frac{1-sqrt[3]{x-1}}{x}
4, limlimits_{xrightarrow-infty}frac{x^2-5x+1}{x^2-2}
5, limlimits_{xrightarrow+infty}frac{2x^2-4}{x^3+3x^2-9}
6, limlimits_{xrightarrow2^-}frac{2x-1}{x-2}
7, limlimits_{xrightarrow3^+}frac{8+x-x^2}{x-3}
8, limlimits_{xrightarrow-infty}left(8+4x-x^3right)
9, limlimits_{xrightarrow-1}frac{sq...
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1, \(\lim\limits_{x\rightarrow1}\frac{2x^2-3x+1}{x^3-x^2-x+1}\)
2, \(\lim\limits_{x\rightarrow2}\frac{x-\sqrt{x+2}}{\sqrt{4x+1}-3}\)
3, \(\lim\limits_{x\rightarrow0}\frac{1-\sqrt[3]{x-1}}{x}\)
4, \(\lim\limits_{x\rightarrow-\infty}\frac{x^2-5x+1}{x^2-2}\)
5, \(\lim\limits_{x\rightarrow+\infty}\frac{2x^2-4}{x^3+3x^2-9}\)
6, \(\lim\limits_{x\rightarrow2^-}\frac{2x-1}{x-2}\)
7, \(\lim\limits_{x\rightarrow3^+}\frac{8+x-x^2}{x-3}\)
8, \(\lim\limits_{x\rightarrow-\infty}\left(8+4x-x^3\right)\)
9, \(\lim\limits_{x\rightarrow-1}\frac{\sqrt[3]{x}+1}{\sqrt{x^2+3}-2}\)
10, \(\lim\limits_{x\rightarrow-\infty}\frac{\left(2x^2+1\right)^2\left(5x+3\right)}{\left(2x^3-1\right)\left(x+1\right)^2}\)
11, \(\lim\limits_{x\rightarrow-\infty}\frac{\sqrt{x^2+2x}}{x+3}\)
12, \(\lim\limits_{x\rightarrow1}\frac{\sqrt{5-x^3}-\sqrt[3]{x^2+7}}{x^2-1}\)
13, \(\lim\limits_{x\rightarrow0}\frac{\sqrt[3]{x+1}+\sqrt{x+4}-3}{x}\)
14, \(\lim\limits_{x\rightarrow0}\frac{\left(x^2+2020\right)\sqrt{1+3x}-2020}{x}\)
15, \(\lim\limits_{x\rightarrow+\infty}\left(2x-\sqrt{4x^2-3}\right)\)
16, \(\lim\limits_{x\rightarrow a}\frac{x^2-\left(a+1\right)x+a}{x^3-a^3}\)
17, \(\lim\limits_{x\rightarrow1}\frac{x^n-nx+n-1}{\left(x-1\right)^2}\)
18, \(f\left(x\right)=\left\{{}\begin{matrix}\frac{x^2-2x}{8-x^3}\\\frac{x^4-16}{x-2}\end{matrix}\right.\) khi x>2,khi x<2 tại x=2
a,^{lim}_{x-2}frac{sqrt[3]{8x+11}-sqrt{x+7}}{x^2-3x+2}
b, ^{lim}_{x-0}frac{2sqrt{1+x}-sqrt[3]{8-x}}{x}
c, ^{lim}_{x-1}frac{sqrt{5-x^3}-sqrt[3]{x^2+7}}{x^2-1}
d,^{lim}_{x-0}frac{sqrt{1+2x}.sqrt[3]{1+4x}-1}{x}
e,^{lim}_{x-1}frac{x^4-1}{x^3-2x^2+x}
f,^{lim}_{x-1}left(frac{1}{1-x}-frac{3}{1-x^3}right)
Đọc tiếp
a,\(^{lim}_{x->2}\frac{\sqrt[3]{8x+11}-\sqrt{x+7}}{x^2-3x+2}\)
b, \(^{lim}_{x->0}\frac{2\sqrt{1+x}-\sqrt[3]{8-x}}{x}\)
c, \(^{lim}_{x->1}\frac{\sqrt{5-x^3}-\sqrt[3]{x^2+7}}{x^2-1}\)
d,\(^{lim}_{x->0}\frac{\sqrt{1+2x}.\sqrt[3]{1+4x}-1}{x}\)
e,\(^{lim}_{x->1}\frac{x^4-1}{x^3-2x^2+x}\)
f,\(^{lim}_{x->1}\left(\frac{1}{1-x}-\frac{3}{1-x^3}\right)\)
Bài 1
a. limlimits_{xrightarrow-infty}frac{sqrt{4x^2}+1}{3x-1}
b. limlimits_{xrightarrow+infty}frac{sqrt{9x^2+x+1}-sqrt{4x^2+2x+1}}{x+1}
c. limlimits_{xrightarrow+infty}frac{sqrt{x+2x+3}+4x+1}{sqrt{4x^2+1}+2-x}
d. limlimits_{xrightarrow+infty}frac{3x-2sqrt{x}+sqrt{x^4-5x}}{2x^2+4x-5}
Bài 2
a. limlimits_{xrightarrow-infty}frac{2x+1}{x-1}
b. limlimits_{xrightarrow-infty}frac{2x^3+3}{x^3-2x^2+1}
c. limlimits_{xrightarrow+infty}frac{left(3x^2+1right)left(5x+3right)}{left(2x^3-1r...
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Bài 1
a. \(\lim\limits_{x\rightarrow-\infty}\frac{\sqrt{4x^2}+1}{3x-1}\)
b. \(\lim\limits_{x\rightarrow+\infty}\frac{\sqrt{9x^2+x+1}-\sqrt{4x^2+2x+1}}{x+1}\)
c. \(\lim\limits_{x\rightarrow+\infty}\frac{\sqrt{x+2x+3}+4x+1}{\sqrt{4x^2+1}+2-x}\)
d. \(\lim\limits_{x\rightarrow+\infty}\frac{3x-2\sqrt{x}+\sqrt{x^4-5x}}{2x^2+4x-5}\)
Bài 2
a. \(\lim\limits_{x\rightarrow-\infty}\frac{2x+1}{x-1}\)
b. \(\lim\limits_{x\rightarrow-\infty}\frac{2x^3+3}{x^3-2x^2+1}\)
c. \(\lim\limits_{x\rightarrow+\infty}\frac{\left(3x^2+1\right)\left(5x+3\right)}{\left(2x^3-1\right)\left(x+4\right)}\)
Tính các giới hạn sau đây :
L_1limfrac{x^3+3x^2-2x}{x^5+4x}left(xrightarrow0right)
L_2limfrac{x^3-3x+2}{left(4-2xright)^3}left(xrightarrow+inftyright)
L_3limfrac{2x^2+3x+1}{x^2+x}left(xrightarrow-1right)
L_4limfrac{x^2-4x+1}{4-x^2}left(xrightarrow2right)
L_5limfrac{sqrt{x+1}-2}{x-2}left(xrightarrow3right)
L_6limfrac{sqrt{x+3}-x-1}{x^2-1}left(xrightarrow1right)
L_7limleft(sqrt{x^2+x+1}-x+1right)left(xrightarrow+inftyright)
L_8limleft(sqrt{x^2+x+1}-3x+2right)left(xrightarrow-...
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Tính các giới hạn sau đây :
\(L_1=lim\frac{x^3+3x^2-2x}{x^5+4x}\left(x\rightarrow0\right)\)
\(L_2=lim\frac{x^3-3x+2}{\left(4-2x\right)^3}\left(x\rightarrow+\infty\right)\)
\(L_3=lim\frac{2x^2+3x+1}{x^2+x}\left(x\rightarrow-1\right)\)
\(L_4=lim\frac{x^2-4x+1}{4-x^2}\left(x\rightarrow2\right)\)
\(L_5=lim\frac{\sqrt{x+1}-2}{x-2}\left(x\rightarrow3\right)\)
\(L_6=lim\frac{\sqrt{x+3}-x-1}{x^2-1}\left(x\rightarrow1\right)\)
\(L_7=lim\left(\sqrt{x^2+x+1}-x+1\right)\left(x\rightarrow+\infty\right)\)
\(L_8=lim\left(\sqrt{x^2+x+1}-3x+2\right)\left(x\rightarrow-\infty\right)\)
tìm các giới hạn sau:
a; \(\lim\limits_{x\rightarrow1}\frac{2x^4-5x^3+3x^2+1}{3x^4-8x^3+6x^2-1}\)
b; \(\lim\limits_{x\rightarrow1}\frac{x^3-3x^2+2}{x^4-4x+3}\)
c; \(\lim\limits_{x\rightarrow1}\frac{x^3-2x-1}{x^5-2x-1}\)
d; \(\lim\limits_{x\rightarrow-1}\frac{\left(x+2\right)^2-1}{x^2-1}\)
a. limlimits_{xrightarrow a}frac{xsqrt{x}-asqrt{a}}{sqrt{x}-sqrt{a}} e. limlimits_{xrightarrow0}frac{sqrt{1+x}-sqrt[3]{1+x}}{x}
b. limlimits_{xrightarrow1}frac{sqrt[n]{x}-1}{sqrt[m]{x}-1}left(m,nin Z^+right) f. limlimits_{xrightarrow2}frac{sqrt[3]{8x+11}-sqrt{x+7}}{x^2-3x+2}
c. limlimits_{xrightarrow1}frac{left(1-sqrt{x}right)left(1-sqrt[3]{x}right)left(1-sqrt[4]{x}right)left(1-sqrt[5]{x}right)}{left(1-xright)^4}...
Đọc tiếp
a. \(\lim\limits_{x\rightarrow a}\frac{x\sqrt{x}-a\sqrt{a}}{\sqrt{x}-\sqrt{a}}\) e. \(\lim\limits_{x\rightarrow0}\frac{\sqrt{1+x}-\sqrt[3]{1+x}}{x}\)
b. \(\lim\limits_{x\rightarrow1}\frac{\sqrt[n]{x}-1}{\sqrt[m]{x}-1}\left(m,n\in Z^+\right)\) f. \(\lim\limits_{x\rightarrow2}\frac{\sqrt[3]{8x+11}-\sqrt{x+7}}{x^2-3x+2}\)
c. \(\lim\limits_{x\rightarrow1}\frac{\left(1-\sqrt{x}\right)\left(1-\sqrt[3]{x}\right)\left(1-\sqrt[4]{x}\right)\left(1-\sqrt[5]{x}\right)}{\left(1-x\right)^4}\) g. \(\lim\limits_{x\rightarrow1}\frac{\sqrt[3]{3x-2}-\sqrt{2x-1}}{x^3-1}\)
d. \(\lim\limits_{x\rightarrow+\infty}\left(\sqrt{x+\sqrt{x+\sqrt{x}}}-\sqrt{x}\right)\) h. \(\lim\limits_{x\rightarrow1}\frac{\sqrt[3]{x+9}+\sqrt[3]{2x-6}}{x^3+1}\)
tìm các giới hạn sau:
a, limlimits_{xrightarrow1}frac{x^4-1}{x^3-2x^2+1} ( câu a,b chỉ cần thay số vào thôi đúng k ạ nếu là thay số thì k cần trình bày nữa đâu )
b, limlimits_{xrightarrow-1}frac{x^5+1}{x^3+1}
c, limlimits_{xrightarrow3}frac{x^3-5x^2+3x+9}{x^4-8x^2-9}
d, limlimits_{xrightarrow1}frac{x-5x^5+4x^6}{left(1-xright)^2}
e, limlimits_{xrightarrow1}frac{x^m-1}{x^n-1}
f, limlimits_{xrightarrow-2}frac{x^4-16}{x^3+2x^2}
Đọc tiếp
tìm các giới hạn sau:
a, \(\lim\limits_{x\rightarrow1}\frac{x^4-1}{x^3-2x^2+1}\) ( câu a,b chỉ cần thay số vào thôi đúng k ạ nếu là thay số thì k cần trình bày nữa đâu )
b, \(\lim\limits_{x\rightarrow-1}\frac{x^5+1}{x^3+1}\)
c, \(\lim\limits_{x\rightarrow3}\frac{x^3-5x^2+3x+9}{x^4-8x^2-9}\)
d, \(\lim\limits_{x\rightarrow1}\frac{x-5x^5+4x^6}{\left(1-x\right)^2}\)
e, \(\lim\limits_{x\rightarrow1}\frac{x^m-1}{x^n-1}\)
f, \(\lim\limits_{x\rightarrow-2}\frac{x^4-16}{x^3+2x^2}\)
tìm các giới hạn sau:
a, \(\lim\limits_{x\rightarrow-3}\frac{x+\sqrt{3-2x}}{x^2+3x}\)
b, \(\lim\limits_{x\rightarrow0}\frac{\sqrt{x+9}+\sqrt{x+16}-7}{x}\)
c, \(\lim\limits_{x\rightarrow\frac{1}{2}}\frac{8x^2-1}{6x^2-5x+1}\)
d, \(\lim\limits_{x\rightarrow0}\frac{\sqrt{x^2+1}-1}{4-\sqrt{x^2+16}}\)
Mọi người giải giúp em bài này với!
1,\(\lim\limits_{x\rightarrow+\infty}\frac{x^4+8x}{x^3+2x^2+x+2}\)
2,\(\lim\limits_{x\rightarrow-\infty}\frac{1+3x}{\sqrt{2x^2+3}}\)
3,\(\lim\limits_{x\rightarrow-\infty}\frac{\sqrt[3]{1+x^4+x^6}}{\sqrt{1+x^3+x^4}}\)