Question

\(/x+\frac{1}{3}/=11\)

Answer 1

TH1: \(x+\frac{1}{3}=11\)

<=> \(x=\frac{32}{3}\)

TH2: \(x+\frac{1}{3}=-11\)

<=> x = \(\frac{-34}{3}\)

KL: \(x\in\left\{\frac{32}{3};\frac{-34}{3}\right\}\)

Answer 2

\(\left|x+\frac{1}{3}\right|=11\)

\(=>\left[{}\begin{matrix}x+\frac{1}{3}=11\\x+\frac{1}{3}=-11\end{matrix}\right.=>\left[{}\begin{matrix}x=11-\frac{1}{3}\\x=-11-\frac{1}{3}\end{matrix}\right.=>\left[{}\begin{matrix}x=\frac{32}{3}\\x=-\frac{34}{3}\end{matrix}\right.\)(T/M)

Vậy......

Answer 3

|x+1/3|=11

TH1

x+1/3=11

x=11-1/3

x=32/3

TH2

x+1/3=-11

x=-11-1/3

x=-34/3

Vậy x€{32/3 ; -34/3